Was my question too brief? I'm using MIPS5Kf core included in a Broadcom
implemented processor and it has a 32kB d-cache and a same sized i-cache.
Cache configuration is 2-way, 32-byte cacheline for both d- and i-cache
without L2 cache. Of course, MIPS-port Linux as the kernel for it. And, a
onboard block device has problem in its operation. I don't think it's a
kernel problem. So I wanna inspect the contents of cache RAMs at the device
driver's context. I've added some lines of codes look like follow:
"cache 5, 0x00(%3)\n\t" // load d-cache tag
".set mips0\n\t" // by index
"mfc0 %0, $28, 0\n\t"
"mfc0 %1, $28, 1\n\t"
"mfc0 %2, $29, 1\n\t"
: "=r" (tag), "=r" (data_lo), "=r" (data_hi)
: "r" (0x80000000 | (way << 14) | (index << 5) | (word <<
This is executed for every index, every way, and every word. The thing aches
my head is the tags from a single cacheline differs. (very often for
d-cache) So I modified the code to reread the cacheline from the first word
when the tag was modified before reading all four words. Then the code never
return. I couldn't find any related information from manual.
Please give me a hint for reading whole cacheline safely.
[mailto:email@example.com] On Behalf Of Kim, Jong-Sung
Sent: Tuesday, April 18, 2006 9:37 AM
Subject: Reading an entire cacheline
Is there any way to read an entire cacheline from the MIPS5Kf? Four
sequential cache instructions do similarly, but sometimes the tags from a
same cacheline differ. How can I read a consistent cacheline safely?