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Re: Questions?

To: Ralf Baechle <>
Subject: Re: Questions?
From: Richard Hodges <>
Date: Thu, 7 Mar 2002 09:56:58 -0800 (PST)
Cc: Linux MIPS <>
In-reply-to: <>
On Thu, 7 Mar 2002, Ralf Baechle wrote:

> The MIPS ABI only covers big endian systems - every "real" MIPS UNIX
> system is big endian.  Everything else is a GNU extension.  There is
> hardly any reason to choose a particular byteorder as usually endianess
> swapping takes so little CPU time that it isn't even meassurable but so
> I'm told there are exceptions.

To me, byte swapping on MIPS actually seems rather expensive.  The code
for htonl (linux/byteorder/swab.h) ends up something like this:

        srl     $5,$4,8
        andi    $5,$5,0xff00
        srl     $2,$4,24
        andi    $3,$4,0xff00
        or      $2,$2,$5
        sll     $3,$3,8
        or      $2,$2,$3
        sll     $4,$4,24

This may not be an issue if it is only needed a few times per packet, but
my system must byte-swap (LE to BE) about 500KB (or 4mb) per second.
Actually, I save a bit of work by combining the byte swapping with the
memory move, just after copy_from_user, and looks something like:

    unsigned char a, b, c, d, *mptr;
        a = mptr[0];
        b = mptr[1];
        c = mptr[2];
        d = mptr[3];
        mptr[0] = d;
        mptr[1] = c;
        mptr[2] = b;
        mptr[3] = a;

This method works, but it is still 8 instructions per word.  Yuck!  Does
anyone know of a _decent_ way to handle this on MIPS?

All the best,


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