| To: | Maxin John <maxin.john@gmail.com> |
|---|---|
| Subject: | Re: kmemleak for MIPS |
| From: | Daniel Baluta <dbaluta@ixiacom.com> |
| Date: | Wed, 30 Mar 2011 14:24:59 +0300 |
| Cc: | naveen yadav <yad.naveen@gmail.com>, linux-mips@linux-mips.org, linux-kernel@vger.kernel.org, linux-mm@kvack.org, Catalin Marinas <catalin.marinas@arm.com>, Eric Dumazet <eric.dumazet@gmail.com> |
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We have:
> UDP hash table entries: 128 (order: 0, 4096 bytes)
> CONFIG_BASE_SMALL=0
udp_table_init looks like:
if (!CONFIG_BASE_SMALL)
table->hash = alloc_large_system_hash(name, .. &table->mask);
/*
* Make sure hash table has the minimum size
*/
Since CONFIG_BASE_SMALL is 0, we are allocating the hash using
alloc_large_system
Then:
if (CONFIG_BASE_SMALL || table->mask < UDP_HTABLE_SIZE_MIN - 1) {
table->hash = kmalloc();
table->mask is 127, and UDP_HTABLE_SIZE_MIN is 256, so we are allocating again
table->hash without freeing already allocated memory.
We could free table->hash, before allocating the memory with kmalloc.
I don't fully understand the condition table->mask < UDP_HTABLE_SIZE_MIN - 1.
Eric?
thanks,
Daniel.
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