| To: | bamakhrama@gmail.com |
|---|---|
| Subject: | Re: Average number of instructions per line of kernel code |
| From: | "Jesper Juhl" <jesper.juhl@gmail.com> |
| Date: | Thu, 30 Aug 2007 15:31:12 +0200 |
| Cc: | linux-mips@linux-mips.org, linux-kernel@vger.kernel.org |
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| In-reply-to: | <40378e40708300600h5837d46ci5266b8ae62bbd46e@mail.gmail.com> |
| Original-recipient: | rfc822;linux-mips@linux-mips.org |
| References: | <40378e40708300600h5837d46ci5266b8ae62bbd46e@mail.gmail.com> |
| Sender: | linux-mips-bounce@linux-mips.org |
On 30/08/2007, Mohamed Bamakhrama <bamakhrama@gmail.com> wrote: > Hi all, > I have a question regarding the average number of assembly > instructions per line of kernel code. I know that this is a difficult > question since it depends on many factors such as the instruction set > architecture, compiler used, optimizations used, type of code, coding > style, etc... > I would like to know a rough estimate for such a quantity for the > kernel 2.4/2.6 code running on MIPS32 architecture. > My estimate is between 5-10 instructions. I googled for such a thing > but couldn't find any useful papers/resources. > Why don't you simply count the number of non-blank non-comment lines in the source files that you are building, build the kernel and then count the number of instructions in the resulting binary ? -- Jesper Juhl <jesper.juhl@gmail.com> Don't top-post http://www.catb.org/~esr/jargon/html/T/top-post.html Plain text mails only, please http://www.expita.com/nomime.html |
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