| To: | Pete Popov <ppopov@mvista.com> |
|---|---|
| Subject: | arch/mips/au1000/common/irq.c |
| From: | Jeff Baitis <baitisj@evolution.com> |
| Date: | Thu, 13 Mar 2003 10:47:04 -0800 |
| Cc: | linux-mips@linux-mips.org |
| Original-recipient: | rfc822;linux-mips@linux-mips.org |
| Reply-to: | baitisj@evolution.com |
| Sender: | linux-mips-bounce@linux-mips.org |
| User-agent: | Mutt/1.2.5i |
Pete:
I've got a question concerning irq.c. In intc0_req0_irqdispatch() (linux_2_4
branch) on lines 545 thru 552, the code reads:
for (i=0; i<32; i++) {
if ((intc0_req0 & (1<<i))) {
intc0_req0 &= ~(1<<i);
do_IRQ(irq, regs);
break;
}
irq++;
}
My question is: why do we increment i and irq independently?
Why doesn't the code read:
for (i=0; i<32; i++) {
if ((intc0_req0 & (1<<i))) {
intc0_req0 &= ~(1<<i);
do_IRQ(i, regs);
break;
}
}
Thanks for your help!
-Jeff
--
Jeffrey Baitis - Associate Software Engineer
Evolution Robotics, Inc.
130 West Union Street
Pasadena CA 91103
tel: 626.535.2776 | fax: 626.535.2777 | baitisj@evolution.com
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