I've got a simple lock-contention program that I'm using to see how
the usema stuff works.
When I try to run the program under par, though, it only lets me trace
one of the invocations:
1 [shaver@linus ~/work/usema]$ par -s -SS -l -o lock-p.par ./lock p
1 Creating new lock.
1 Storing lock.
1 Getting lock.
(now I start the second one)
2 [shaver@linus ~/work/usema]$ par -s -SS -l -o lock-c2.par ./lock c
2 Cannot syscall trace pid 23779:Resource busy
2 Finding existing lock.
2 Getting lock.
2 [shaver@linus ~/work/usema]$
(back to the shell!)
(release the lock on the first invocation)
1 Releasing lock.
1 [shaver@linus ~/work/usema]$
(and now I get more output from the second invocation)
2 [shaver@linus ~/work/usema]$ Waiting...
2 Releasing lock.
Under normal circumstances (no par), I have to press enter on the
second one as well for it to release the lock and exit. When par is
doing its (arguably weird, maybe broken) thing, I don't have to do
Is this a known problem?
#> Mike Shaver (firstname.lastname@example.org) Ingenia Communications Corporation
#> Linux: because every cycle counts.
#> "I don't know what you do for a living[...]" -- email@example.com
#> "I change the world." -- firstname.lastname@example.org